... and explain graphically why the iteration is approaching the fixed point of the function g(x). Here, several substitutions must be made in order to graph the iteration. First, we know that when n = 0, x1 = 1. When we increase the value of n by 1, x2= g(x1), but from part (a), we also know that g(x) = cos x. So from this, we can also state that that is the same thing as g(x1) = cos x1. Hence, if we make the substitution, it would result to x2= cos x1, where we can further substitute the x1 to 1, making the whole equation x2= cos 1. This would then be the first iteration. Subsequently, this entire substitution process would be repeated another four times, each time using the previous answer as a substitute. The calculations below will provide a better understanding of the concept. 1st iteration, n = ...

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