... level road from the propulsive force of the gear engaged. As it is desired to have as much propulsive force as possible, one does not change from the initial gear until the gear has exhausted its maximum vehicle speed. It has been demonstrated on the graph how to calculate the figures. However, since accuracy is important, the NPF has been worked out by using the equations of the propulsive and resistive curves. Once the acceleration is calculated, the time taken for achieving the new speed is found by using the classic Newton's Second Law: v = u + at Where v = Final Velocity u = Initial Velocity a = Acceleration t = Acceleration Time Gear Velocity Band (km/hr) Propulsive Force (kN) Resistive Force (kN) Net Propulsive Force (kN) Average Force (kN) Average Acceleration (m/s2) Time Taken (s) 1 0 0.17 0.169 0.00 1 5 5.97 0.17 5.80 2.90 2.15 0.65 1 10 6.31 0.17 6.14 5.97 4.43 0.31 1 15 6.59 0.18 6.41 6.27 4.65 0.30 1 20 6.79 0.19 6.60 6.50 4.82 0.29 1 25 6.91 0.20 6.72 6.66 4.94 0.28 1 30 6.96 0.21 6.76 6.74 5.00 0.28 1 35 6.94 0.22 6.72 6.74 5.00 0.28 1 40 6.85 0.24 6.61 6.67 4.94 0.28 1 45 6.68 0.25 6.42 6.52 4.83 0.29 1 50 6.43 0.27 6.16 6.29 4.67 0.30 1 55 6.12 0.30 5.82 5.99 4.44 0.31 2 60 4.35 0.321 4.03 4.93 3.65 0.38 2 65 4.30 0.348 3.96 3.99 2.96 0.47 2 70 4.23 0.376 3.86 3.91 2.90 0.48 2 75 4.15 0.407 3.74 3.80 2.82 0.49 2 80 4.04 0.440 3.60 3.67 2.72 0.51 2 85 3.92 0.475 3.44 3.52 2.61 0.53 3 88 3.03 0.50 2.53 2.99 2.22 0.38 3 90 3.023 0.5121 2.51 2.98 2.21 0.63 total time taken 7.43 Assume it takes 1 second to pull away and 0.5 second for each gear change. Then the total time taken would be 7.43 + (0.5 x ...

See this essay or coursework document in full right now