Gain Immediate access to our Essays
FREE access exchanged for your work, or pay £9.99
Words: | Submitted: Tue Jun 20 2006
... water= (96.97g- 2.35g) ±0.02g = 94.62g ±0.02g Initial Temperature= 72? ± 1? Final Temperature= 33? ± 1? ?Temperature change= (72?- 33?) ± 2? = 39? ± 2? Final mass= 124.56g ±0.01g ? Mass of water inside= 122.21g ±0.01g ? Mass of ice added= (122.21g- 94.62g) ±0.02g = 27.59g ±0.02g Calculation for the Latent heat of fusion of ice in observation no.1: EQ: Energy gained of ice= Energy loss of water mici?? + mil + micw?? = mwcw?? (0.02759) (2100)ii (17) + (0.02759) l + (0.02759) (4186)iii (33) = (0.09462) (4186) (39) l = 386042 (Jkg-1)iv l = 3.86x 105 (Jkg-1) Calculations for uncertainties: For mici??, ?E1/ E1= ?mi / mi + ???/ ?? ?E1= (0.02/ 27.59 + 1 /17) (0.02759) (2100) (17) ?E1= ± 58.653(J) For micw??, ?E2/ E2= ?mi / mi + ???/ ?? ?E2=(0.02/ 27.59 + 1/ 33) (0.02759) (4186) (33) ?E2= ± 118.2545 (J) For mwcw??, ?E3/ E3= ?mw / mw + ???/ ?? ?E3= (0.02/ 94.62 + 2/ 39) (0.09462) (4186) (39) ?E3= ± 795.4237 ...
FREE access exchanged for your work, or pay £9.99